本文是小编为大家收集整理的关于增量操作的不可预测结果的处理/解决方法，可以参考本文帮助大家快速定位并解决问题，中文翻译不准确的可切换到English标签页查看源文。
问题描述
以下 C++ 代码的行为是否有任何原因?
诠释我;
我=1；cout <<(++i)++;输出:2
我=1；cout <<++(++i);输出:3
我=1；cout <<(i++)++;输出:错误.需要左值
我=1；cout <<++(i++);输出:错误.需要 LValue
推荐答案
bintom 写道:以下 C++ 代码的行为是否有任何原因?因为这是荒谬的未定义行为.
诠释我;
我=1；cout <<(++i)++;输出:2
--
伊恩·柯林斯.
伊恩·柯林斯写道:bintom 写道:为什么没有意义?为什么是未定义的?>下面的 C++ 代码的行为有什么原因吗?因为这是荒谬的未定义行为.
int i;
i=1;cout <<(++i)++;输出:2
五
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Victor Bazarov 写道:伊恩·柯林斯写道:你是对的，两者都不是.抱歉，我看到的帖子太多了>bintom 写道:>>以下 C++ 代码的行为是否有任何原因?因为这是荒谬的未定义行为.
int i;
i=1;cout <<(++i)++;输出:2
为什么没有意义?为什么未定义?
是和做...
--
伊恩·柯林斯.
问题描述
Is there any reason why the following C++ code behaves as it does ?
int i;
i=1; cout << (++i)++; Output: 2
i=1; cout << ++(++i); Output: 3
i=1; cout << (i++)++; Output: Error. LValue required
i=1; cout << ++(i++); Output: Error. LValue required
推荐答案
bintom wrote:Is there any reason why the following C++ code behaves as it does ?Because it''s nonsensical undefined behaviour.
int i;
i=1; cout << (++i)++; Output: 2
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Ian Collins.
Ian Collins wrote:bintom wrote:Why is it non-sensical? Why is it undefined?>Is there any reason why the following C++ code behaves as it does ?Because it''s nonsensical undefined behaviour.
int i;
i=1; cout << (++i)++; Output: 2
V
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Victor Bazarov wrote:Ian Collins wrote:You are right, it is neither. Sorry, I''ve seen way too many posts that>bintom wrote:>>Is there any reason why the following C++ code behaves as it does ?Because it''s nonsensical undefined behaviour.
int i;
i=1; cout << (++i)++; Output: 2
Why is it non-sensical? Why is it undefined?
are and do...
--
Ian Collins.
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