如何获得准确的xpath？

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问题描述

你好，
我有以下名为 memberDoc 的 xmldocument:

<ROOT>- <tblmembers><facilityid>A</facilityid><memberid>000000001</memberid><附加信息><adtsource>HIS</adtsource><耐心附加信息 id="1"><patempid>TMH</patempid><patempname>The METHODIST HOSPITAL</patempname><patempstatus>F</patempstatus><patempoccupation>IT</patempoccupation><patempphone></patempphone><patempaddress>6565 FANNIN</patempaddress><patempaddress2></patempaddress2><patempcity>休斯顿</patempcity><patempstate>TX</patempstate><patempzipcode>77030</patempzipcode><patempcountry>美国</patempcountry><patempstartdate>20100101</patempstartdate><patempretirementdate></patempretirementdate><address3>ADDRESS3</address3><oldmemberid></oldmemberid><mname></mname><hipaaonfile></hipaaonfile><hipaadate>12/14/2010</hipaadate><race>C</race><语言></language><宗教>ANG</religion><primcarephysicianid>002249</primcarephysicianid><primcarephysicianlname>CAGE</primcarephysicianlname><primcarephysicianfname>JAMES</primcarephysicianfname><primcarephysicianmname>WILLIAM</primcarephysicianmname><balance></balance></patientadditionalinfo></additionalinfo></tblmembers></ROOT>

现在我需要获取 <race>在 [tblmembers/additionalinfo/patientadditionalinfo[@id=''1'']] 里面.
我写了以下代码:
XmlNodeList member_nodes;                
 member_nodes = memberDoc.SelectNodes("//tblmembers");

string retvalue=member_nodes[0].SelectSingleNode("//additionalinfo/patientadditionalinfo[@id=''1'']/race").InnerText;


在这里，我得到的是"".
你能帮我什么应该是正确的 XPath 或者我到底在哪里失踪?

提前谢谢，
Avishek推荐答案
出了什么问题
string retvalue = memberDoc.SelectSingleNode("ROOT/tblmembers/additionalinfo/patientadditionalinfo[@id='1']/race").InnerText;

?

我将您提供的内容复制并粘贴到名为"test.xml"的文件中(当然从第二行删除了多余的破折号)

并测试了这段代码:
XmlDocument rawXMLData = new XmlDocument();StreamReader reader = new StreamReader(@"d:\test.xml");rawXMLData.LoadXml(reader.ReadToEnd());var result = rawXMLData.SelectNodes("ROOT/tblmembers/附加信息/患者附加信息[@id='1']/race");foreach (XmlNode 节点 in 结果)Console.WriteLine(node.Name + " = " + node.InnerText);Console.ReadLine();


它打印:
race = C

但是我可以编写 XPath，但我从 Pallini 的回答中获取了 XPath ;)

希望对您有所帮助.


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问题描述

Hi,
I have the following xmldocument named as memberDoc:

<ROOT>
  - <tblmembers>
    <facilityid>A</facilityid>
    <memberid>000000001</memberid>
    <additionalinfo>
      <adtsource>HIS</adtsource>
      <patientadditionalinfo id="1">
        <patempid>TMH</patempid>
        <patempname>THE METHODIST HOSPITAL</patempname>
        <patempstatus>F</patempstatus>
        <patempoccupation>IT</patempoccupation>
        <patempphone></patempphone>
        <patempaddress>6565 FANNIN</patempaddress>
        <patempaddress2></patempaddress2>
        <patempcity>HOUSTON</patempcity>
        <patempstate>TX</patempstate>
        <patempzipcode>77030</patempzipcode>
        <patempcountry>USA</patempcountry>
        <patempstartdate>20100101</patempstartdate>
        <patempretirementdate></patempretirementdate>
        <address3>ADDRESS3</address3>
        <oldmemberid></oldmemberid>
        <mname></mname>
        <hipaaonfile></hipaaonfile>
        <hipaadate>12/14/2010</hipaadate>
        <race>C</race>
        <language></language>
        <religion>ANG</religion>
        <primcarephysicianid>002249</primcarephysicianid>
        <primcarephysicianlname>CAGE</primcarephysicianlname>
        <primcarephysicianfname>JAMES</primcarephysicianfname>
        <primcarephysicianmname>WILLIAM</primcarephysicianmname>
        <balance></balance>
      </patientadditionalinfo>
    </additionalinfo>
  </tblmembers>
</ROOT>

Now I need to fetch the <race> which is inside [tblmembers/additionalinfo/patientadditionalinfo[@id=''1'']].
I have written the following code:

XmlNodeList member_nodes;                
 member_nodes = memberDoc.SelectNodes("//tblmembers");

string retvalue=member_nodes[0].SelectSingleNode("//additionalinfo/patientadditionalinfo[@id=''1'']/race").InnerText;

Here I am getting the as "".
Can you please help me what should be the correct XPath or where exactly I am missing?

Thanks in advance,
Avishek

推荐答案

What''s wrong with

string retvalue = memberDoc.SelectSingleNode("ROOT/tblmembers/additionalinfo/patientadditionalinfo[@id='1']/race").InnerText;

I copied and pasted what you have provided into a file named "test.xml" (of course removed that extra dash from second line)

and tested this code :
XmlDocument rawXMLData = new XmlDocument();
StreamReader reader = new StreamReader(@"d:\test.xml");

rawXMLData.LoadXml(reader.ReadToEnd());

var result = rawXMLData.SelectNodes("ROOT/tblmembers/additionalinfo/patientadditionalinfo[@id='1']/race");

foreach (XmlNode node in result)
   Console.WriteLine(node.Name + " = " + node.InnerText);

Console.ReadLine();
And it prints :
race = C
However I can write the XPath but I took the XPath from Pallini''s answer ;)

Hope it helps.

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