问题描述
给定一个数据库表,一个列名 C 和一个大于 1 的数字 N,我怎样才能得到一组具有相同值的列 C 至少有 N 行的行?如果存在多个这样的组,我需要获取包含最新条目的组(具有最大 Id 的组).
是否可以使用 LINQ to Entities 做到这一点?
Example: > Id | Mycolumn > - - - - - - - > 1 | name55555 > 2 | name22 > 3 | name22 > 4 | name22 > 5 | name55555 > 6 | name55555 > 7 | name1 Primary Key: ID OrderBy: ID Repeated column: Mycolumn
如果 N = 3 和 C = Mycolumn,那么我们需要获取列 MyColumn 至少重复 3 次的行.
对于上面的示例,它应该返回第 1、5 和 6 行,因为 name55555 的最后一个索引是 6,而 name22 的最后一个索引(也重复 3 次)是 4.
推荐答案
data.Mytable .OrderByDescending(m => m.Id) .GroupBy(m => m.Mycolumn) .FirstOrDefault(group => group.Count() >= N) .Take(N) .Select(m => m.Id)
问题描述
Given a database table, a column name C, and a number N larger than 1, how can I get a group of rows with equal values of column C which has at least N rows? If there exists more than one such group, I need to get the group which contains the newest entry (the one with the largest Id).
Is it possible to do this using LINQ to Entities?
Example: > Id | Mycolumn > - - - - - - - > 1 | name55555 > 2 | name22 > 3 | name22 > 4 | name22 > 5 | name55555 > 6 | name55555 > 7 | name1 Primary Key: ID OrderBy: ID Repeated column: Mycolumn
If N = 3 and C = Mycolumn, then we need to get rows which have the column MyColumn duplicated at least 3 times.
For the example above, it should return rows 1, 5 and 6, because last index of name55555 is 6, and last index of name22 (which is also repeated 3 times) is 4.
推荐答案
data.Mytable .OrderByDescending(m => m.Id) .GroupBy(m => m.Mycolumn) .FirstOrDefault(group => group.Count() >= N) .Take(N) .Select(m => m.Id)