如何在XML中获得具有名称空间的特定节点?[英] How to get an specific node in xml with namespaces?

本文是小编为大家收集整理的关于如何在XML中获得具有名称空间的特定节点?的处理/解决方法,可以参考本文帮助大家快速定位并解决问题,中文翻译不准确的可切换到English标签页查看源文。

问题描述

我正在交易以访问XML文档的特定节点.我意识到这是一个基本名称空间.这是一个例子.

在此处输入图像说明

我有兴趣从所有后代节点(entry)中获取节点d:mediaurl的值.我还没有完成.

当我调试变量迭代器'i'时,我可以看到XML再次包含默认名称空间,例如:

<entry xmlns="http://schemas.microsoft.com.ado/..." 

,我还必须包括另一个名为" D"的名称空间.

我该怎么办才能访问该特定节点?

这就是我所拥有的.

        var doc = XDocument.Parse(result);

        string BASE_NS = "http://www.w3.org/2005/Atom";

        string d = "http://schemas.microsoft.com/ado/2007/08/dataservices";
        var query = from i in doc.Descendants(XName.Get("entry", BASE_NS))
                    select new Image()
        {
            Url = i.Element(XName.Get("MediaUrl", BASE_NS)).Value
        };

        var results = query.ToList();

推荐答案

我建议使用XNamespace而不是XName(个人喜好,主要是 - 这是我一直在linq中与XML中的名称空间打交道的方式).对我来说,提前设置名称空间,然后使用Element(NS + "element name") than to use xname.get (though using xname.get'的努力较少.

如果您想获得每个条目的所有"媒体"元素,那么我会做这样的事情:

XNamespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices";

var query = (from i in doc.Descendants(d + "MediaUrl")
             select new Image()
             {
                 Url = i.Value
             }).ToList();

如果您只想获得其中一个,那么您需要做一些不同的事情,具体取决于您想要得到的.

用于属性媒体:

XNamespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices";
XNamespace m = "http://schemas.microsoft.com/ado/2007/08/dataservices/metadata";

var query = (from i in doc.Descendants(m + "properties")
             select new Image()
             {
                 Url = i.Element(d + "MediaUrl").Value
             }).ToList();

对于缩略图媒体:

XNamespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices";

var query = (from i in doc.Descendants(d + "Thumbnail")
             select new Image()
             {
                 Url = i.Element(d + "MediaUrl").Value
             }).ToList();

这里的关键是将命名空间与元素名称结合使用以检索它.

其他推荐答案

var query = from i in doc.Descendants("{full namespace for prefix d}MediaUrl")
                    select new Image()
        {
            Url = i.Value
        };

本文地址:https://www.itbaoku.cn/post/1557184.html

问题描述

I'm dealing to access an specific node from a XML Document. I realized that this one as a base namespace. Here is the example.

enter image description here

I'm interested to get the value of the node d:MediaUrl from all descendents node (entry). And I haven't accomplished that.

When I debug the variable iterator 'i', I can see that the XML includes the default namespace again, something like:

<entry xmlns="http://schemas.microsoft.com.ado/..." 

And also I have to include the another namespace called 'd'.

What can I do to access to that particular nodes?

This is what I have.

        var doc = XDocument.Parse(result);

        string BASE_NS = "http://www.w3.org/2005/Atom";

        string d = "http://schemas.microsoft.com/ado/2007/08/dataservices";
        var query = from i in doc.Descendants(XName.Get("entry", BASE_NS))
                    select new Image()
        {
            Url = i.Element(XName.Get("MediaUrl", BASE_NS)).Value
        };

        var results = query.ToList();

推荐答案

I would suggest using XNamespace rather than XName (personal preference, mainly - as that's how I've always dealt with namespaces in LINQ to XML). To me it's less effort to set up the namespaces in advance and then use Element(NS + "element name") than to useXName.Get(though usingXName.Get` is perfectly fine if that's what you want to do.

If you want to get a all the "MediaUrl" elements for each entry, then I'd do something like this:

XNamespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices";

var query = (from i in doc.Descendants(d + "MediaUrl")
             select new Image()
             {
                 Url = i.Value
             }).ToList();

If you want to get only one of them, then you need to do something a little different, depending on which one you wanted to get.

For the properties MediaUrl:

XNamespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices";
XNamespace m = "http://schemas.microsoft.com/ado/2007/08/dataservices/metadata";

var query = (from i in doc.Descendants(m + "properties")
             select new Image()
             {
                 Url = i.Element(d + "MediaUrl").Value
             }).ToList();

For the Thumbnail MediaUrl:

XNamespace d = "http://schemas.microsoft.com/ado/2007/08/dataservices";

var query = (from i in doc.Descendants(d + "Thumbnail")
             select new Image()
             {
                 Url = i.Element(d + "MediaUrl").Value
             }).ToList();

The key here is to use the namespace in conjunction with the element name in order to retrieve it.

其他推荐答案

var query = from i in doc.Descendants("{full namespace for prefix d}MediaUrl")
                    select new Image()
        {
            Url = i.Value
        };