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问题描述
我有一个熊猫系列对象，我想根据值
将其子集例如:
s = pd.Series([1,2,3,4,5,6,7,8,9,10])
如何将其子集归为以便我可以得到一个仅包含更大或x值元素的串联对象. ?
推荐答案
我相信您是指布尔indexing
大于x:
x = 5 >>> s[s > x] # Alternatively, s[s.gt(x)]. 5 6 6 7 7 8 8 9 9 10 dtype: int64
小于x(即在x下):
s[s < x] # or s[s.lt(x)]
其他推荐答案
假设"大或x"您的意思是"不等于x"，您可以使用布尔索引:
s[s!=x]
问题描述
I have a pandas series object, and i want to subset it based on a value
for example:
s = pd.Series([1,2,3,4,5,6,7,8,9,10])
how can i subset it so i can get a series object containing only elements greater or under x value. ?
推荐答案
I believe you are referring to boolean indexing on a series.
Greater than x:
x = 5 >>> s[s > x] # Alternatively, s[s.gt(x)]. 5 6 6 7 7 8 8 9 9 10 dtype: int64
Less than x (i.e. under x):
s[s < x] # or s[s.lt(x)]
其他推荐答案
Assuming that by "greater or under x" you mean "not equal to x", you can use boolean indexing:
s[s!=x]
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