在PhalconPHP中重定向到404路线的结果是空白页[英] Redirecting to 404 route in PhalconPHP results in Blank Page

问题描述

我已经设置了一个路由器,并在其中为 404 定义了一条路由:

<?php

use Phalcon\Mvc\Router;
$router = new Router(FALSE);
$router->removeExtraSlashes(true);

$route = $router->add('/', ['controller' => 'index', 'action' => 'index']);
$route->setName("index");

// other routes defined here...

$router->notFound([
  "controller" => "index",
  "action" => "route404"
]);

?>

我的索引控制器:

<?php

class IndexController extends ControllerBase
{

    public function indexAction()
    {
    // code removd for berevity 
    }

    public function route404Action() {
      // no code here, I just need to show the view.
    }

}
?>

我有一个视图@/app/views/index/route404.phtml,里面只有一点HTML,我什至试着把它做成一个.volt文件,但运气不好.

当我转到与任何路线都不匹配的页面时,它可以正常工作.但是,如果我尝试重定向到它,我只会得到一个空白页.例如,在我的一个控制器中,我有这个:

if (!$category) {
  // show 404

  //Tried this next line to test, and it indeed does what you'd expect, I see "Not Found". 
  // echo "Not Found"; exit;  

  $response = new \Phalcon\Http\Response();
      $response->redirect([
    "for" => "index", 
    "controller" => "index", 
    "action" => "route404"]
  );

  return; // i return here so it won't run the code after this if statement.
}

有什么想法吗?该页面完全空白(源代码中没有任何内容),并且我的 apache 日志中没有错误.

推荐答案

尝试返回响应对象,而不仅仅是一个空白返回.示例:

return $this->response->redirect(...);

但是我建议使用从调度员转发来显示 404 页面.这样,用户将停留在相同的 url 上,浏览器将收到正确的状态码 (404).这种方式对 SEO 也很友好 :)

例子:

if ($somethingFailed) {
    return $this->dispatcher->forward(['controller' => 'index', 'action' => 'error404']);
}  

// Controller method
function error404Action()
{   
    $this->response->setStatusCode(404, "Not Found"); 
    $this->view->pick(['_layouts/error-404']);
    $this->response->send();
}    

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